Explain Fermat's last theorem by a three-way deadlock-新党あい

I do not know the rules of how to solve mathematics properly, but I will explain Fermat's last theorem.

First, there are three people of X, Y, Z.

They play the game of scissors-paper-rock.

To equilibrate with three people, they must be scissors-paper-rock at the same time.

It is the same for 3 people with 3 choices.

When choices are represented by n + 1, there are 3 people, so n = 2.

But if n is 3, there is another choice besides scissors-paper-rock.

There are one choice that is not chosen among the four choices and three people.

With three people, it is not possible to select all four options and put it in an equilibrium state.

Since n + 1 = 4 is impossible, even if the number increases further, it does not hold.

n + 1 = 3 is n = 2 finished.

Thank you for reading to the end.

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Explain Fermat's last theorem by a three-way deadlock

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